Question

Question 1

A 10 N block is at the bottom of a frictionless incline as shown to the right. How much work must be done against gravity to move it to the top of the incline?

A)600j

B)1000j

C)4800j

D)800j

Answer 1

W = 600 J

Step-by-step explanation:

We have,

According to attached figure,

Height of the inclined plane is 60 m

Force acting on the block is 10 N

It is required to find the work must be done against gravity to move it to the top of the incline. The work done is given by :

W = mgh

or

`W=F* h\\\\W=10* 60\\\\W=600\ J`

So, the work done against the gravity is 600 J.