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Now look at this information


2y + 3 \leqslant 11

What is the largest value that y could be?​

User Deprecated
by
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1 Answer

6 votes

Answer:

4

Explanation:

Given

2y + 3 ≤ 11 ( subtract 3 from both sides )

2y ≤ 8 ( divide both sides by 2 )

y ≤ 4

Since y has to be less than or equal to 4

Then the largest value y could be is 4

User Andrew Culver
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