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A function that models the profit for a new pet-monitoring system shows that there is no profit made until the price reaches

$95 per unit, a maximum profit at a price of $140 per unit, and no profit at a price over $185 per unit. Which graph models
the function?
Graphing

A function that models the profit for a new pet-monitoring system shows that there-example-1
User Badal
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2 Answers

2 votes

Answer:

Graph A!

Explanation:

just passed on edge 2020

User Piko
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3 votes

Answer:

The graph that best fits this model of profit and price per unit is attached to this solution.

Explanation:

A couple of graphs are missing from the question. According to the full question as obtained online, there are a number of graph options, and we are expected to pick the best option. I would not add all the other graphs to limit the chances of deletion due to violating community guidelines.

The function is to model the profits of a new pet-monitoring system, so, if the profits are y and x is the price per unit, y = f(x)

The profits vary as the price per unit varies, there is no profit made until the price reaches

$95 per unit, a maximum profit at a price of $140 per unit, and no profit at a price over $185 per unit.

This description of the curve shows that y is negative at values of x less than $95, then the profits increase when x varies between $95 and $140. The profits reach a maximum at $140 and then the profits start to decline as x increases again, the profits go to 0 at x = $185.

This description shows that the function is a quadratic function with a graph that is n-shaped, peaking at x=185 and the graph crosses the x-axis at x=95 and x=185.

The most fitting graph for this model is attached to this solution provided.

From the graph, all the descriptions above are evident.

Hope this Helps!!!

A function that models the profit for a new pet-monitoring system shows that there-example-1
User Nivir
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6.1k points