Question

Add (3x + 9 / 2x + 6) + (8x + 12 / x^2 + 6x + 9)

Answer 1

`(3x^2+34x+51)/(2x^2+12x+18)`

Explanation:

`(3x+9)/(2x+6)+(8x+12)/(x^2+6x+9)= \\\\\\(3(x+3))/(2(x+3))+(8x+12)/((x+3)(x+3))`

To add these two fractions, you need to make the denominators equal:

`(3(x+3)(x+3))/(2(x+3)(x+3))+(16x+24)/(2(x+3)(x+3))= \\\\\\((3x^2+18x+27)+(16x+24))/(2(x+3)(x+3))= \\\\\\(3x^2+34x+51)/(2(x+3)(x+3))= \\\\\\(3x^2+34x+51)/(2x^2+12x+18)`

Hope this helps!