Question 1

∠A and ∠B are complementary. Find m∠A and m∠B.
m∠ A (15x + 3)*
m∠ B (5x - 13)*

Question 2

Answer:

m∠ A=78°

m∠ B=12°

Explanation:

∠A+∠B=90°

15x+3+5x-13=90

20x-10=90

20x=100

x=5

∠A=(15×5+3)°=(75+3)°=78°

∠B=(5×5-13)°=(25-13)°=12°

Question 3

$m < a =78 \\ m 12\\ solution \\ 15x + 3 + 5x - 13 = 90(sum \: of \: complementary \: angles) \\ or \: 15x + 5x + 3 - 13 = 90 \\ or \: 20x - 10 = 90 \\ or \: 20x = 90 + 10 \\ or \: 20x = 100 \\ or \: x = (100)/(20) \\ x = 5 \\ m < a = 15x + 3 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 15 * 5+ 3 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 78\\ m 50- 13 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 - 13 \\ \: \: \: \: \: \: \: \: \: \: \: \: = 12\\ hope \: it \: helps$

Johannes Wiesner · Answer 1 · 2021-10-13T01:55:35+0000

Answer:

m∠ A=78°

m∠ B=12°

Explanation:

∠A+∠B=90°

15x+3+5x-13=90

20x-10=90

20x=100

x=5

∠A=(15×5+3)°=(75+3)°=78°

∠B=(5×5-13)°=(25-13)°=12°

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

0 Comments

Please log in or register to add a comment.

0 Comments

Please log in or register to add a comment.

Other Questions