Question

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible) Compute the probability that a randomly selected peanut M&M is not orange.

Answer 1

0.77 or 77%

Explanation:

Given:

Percentage of brown peanuts = 12%

Percentage of yellow peanuts = 15%

Percentage of red peanuts = 12%

Percentage of blue peanuts = 23%

Percentage of orange peanuts = 23%

Percentage of green peanuts = 15%

Total = 0.12 + 0.15 + 0.12 + 0.23 + 0.23 + 0.15 = 1

Probability that a randomly selected peanut M&M is not orange:

P(orange)' = 1 - P(orange)

Where,

P(orange) = 23% = 0.23

Thus,

P(orange)' = 1 - 0.23

P(orange) ' = 0.77

Probability that a randomly selected peanut is not orange = 0.77