Question

A student in public administration wants to determine the mean amount members of city councils earn. The error in estimating the mean is to be less than $100 with a 99% level of confidence. The student found a report by the department of labor that estimated the standard deviation to be $1000. What is the required sample size?

Answer 1

663.58

Step-by-step explanation:

From the problem:

E, the maximum allowable error, is $100

The value of z for a 99 percent confidence level is 2.576

Estimate of standard deviation is $1,000.

n = [(z x s)/ E] ^ 2

n = [(2.576 x 1000) / 100}^2

= 25.76^2

=663.58