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SIMULTANOUES EQUATIONS WITH 1 QUADRATIC

SIMULTANOUES EQUATIONS WITH 1 QUADRATIC-example-1

2 Answers

6 votes

Answer:

x = - 0.90, y = 2.30

x = 1.40, y = 9.20

Explanation:

4x² + x= 3x + 5

4x² - 2x - 5 = 0

x = (- b ± √b^2 - 4ac) / 2a

Where:

a = 2

b = - 2

c = - 5

x = (2 ± √4 + 4 * 4 * 5) / 8

= (2 ± √84) / 8

x = (2 - √84) / 8 = (1 - √21 ) / 4

= - 0.90

= (2 + √84) / 8 = (1 + √21 ) / 4 = 1.40

x = - 0.90

y = - 0.90 * 3 + 5

= 2.30

x = 1.40

y= 1.40*3+5

= 9.20

Hope this helps!

User Indika K
by
3.8k points
6 votes

Answer:

x= -0.90, y= 2.30

x= 1.40, y= 9.20

Explanation:

y= 3x+5

y= 4x²+x

  • 4x² + x= 3x + 5
  • 4x² - 2x - 5 = 0
  • x= (-b±√b²-4ac)/2a
  • a=2, b= -2, c= -5
  • x= (2±√4+4*4*5)/8= (2±√84)/8
  • x= (2-√84)/8= (1-√ 21 )/4= -0.90
  • x= (2+√84)/8= (1+√ 21 )/4= 1.40
  • x = -0.90 ⇒ y= -0.90*3+5= 2.30
  • x = 1.40 ⇒ y= 1.40*3+5= 9.20

User Metroids
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