Question

When 0.3 moles of acetylene is burned , total mole number of the products will be? a- 0.30 mol b-0.60 mol c-0.75 mol d-0.90 mol e- 1.2 mol

Answer 1

d. 0.9 mol

Step-by-step explanation:

On this case we have to start with the formula of acetylene:

`C_2H_2`

Now we can write the chemical reaction of combustion:

`C_2H_2~+~O_2~->~CO_2~+~H_2O`

The next step is to balance the reaction:

`2C_2H_2~+~5O_2~->~4CO_2~+~2H_2O`

The molar ratio between
`C_2H_2` and
`CO_2` is 2:4, so:

`0.3~mol~C_2_H_2(4~mol~CO_2)/(2~mol~C_2H_2)=0.6~mol~CO_2`

The molar ratio between
`C_2H_2` and
`H_2O` is 2:2, so:

`0.3~mol~C_2_H_2(2~mol~H_2O)/(2~mol~C_2H_2)=0.3~mol~H_2O`

The total moles would 0.6 + 0.3=0.9 moles.

I hope it helps!