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Question in attachment-example-1
User Psyched
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1 Answer

1 vote

Answer:

The range within 1 standard deviation :155.12 ,328.38

Explanation:

Data: 338+160+210+180+166+272+128+409+240+250+160+300+340+200+194+132+202+180+420+380+325+185+233+198


Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}


Mean =(338+160+210+180+166+272+.........+233+198)/(24)

Mean =241.75


\text{Standard deviation} = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}

Standard deviation =
\sqrt{((338-241.75)^(2)+(160-241.75)^(2)+......+(185-241.75)^(2)+(233-241.75)^(2)+(198-241.75)^(2))/(24-1)}

Standard deviation =86.63

Range within 1 standard deviation :
(\mu-\sigma,\mu+\sigma)

Range within 1 standard deviation :(241.75-86.63,241.75+86.63)

Range within 1 standard deviation :155.12 ,328.38

Hence The range within 1 standard deviation :155.12 ,328.38

User Flickerlight
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