Answer:
f(3π/4) = -π
A = π
b = 2
Explanation:
Given that the function follows the form: f(x) = A sin(bx), then f(0) = 0. Given that the period is π, then at x = π/4 the function reaches a maimum, at x = π/2, f(x) = 0, and at x = 3π/4, f(x) reaches a minimum, which have to be π*(-1) = -π
Given the general equation: f(x) = A sin(bx), its period is calculated as:
period = 2π/b
which is equal to π, then:
2π/b = π
b = 2
Replacing x = π/4 into the equation of the function, we get:
A sin(2(π/4)) = π
A sin(π/2) = π
A = π