Question

A 148 g ball is dropped from a tree 11.0 m above the ground. With what speed would it hit the ground

Answer 1

14.68m/s

Step-by-step explanation:

As per the question, the data provided is as follows

Mass = M = 0.148 kg

Height = h = 11 m

Initial velocity = U = 0 m/s

Final velocity = V

Gravitational force = F

Mass = M

Based on the above information, the speed that hit to the ground is

As we know that

Work to be done = Change in kinetic energy

`F ( S) = ((1)/(2) ) M ( V^2 - U^2 )`

`M g h = ((1)/(2) ) M ( V^2 - U^2 )`

`g h = ((1)/(2) ) ( V^2 - U^2 )`

`V^2 - U^2 = 2gh`

`V^2 - 0 = 2gh`

`V = √(2 g h)`

`= √(2*9.8*11)`

= 14.68m/s