Answer:
( - 3, - 1 ), ( 3, - 1 ) / ( - 3, 11 ), ( 3, 11 )
Explanation:
Let us first consider the distance between points ( - 3, 5 ) and ( 3, 5 );

If these are points that are vertices of the square, it should be that the other 2 points are 6 units farther from these points;


Let us confirm ( -3, - 1 ) and ( 3, - 1 ) are 6 units apart, respectively ( -3, 11 ) and ( 3, 11 ) to say they are the other two vertices;


Thus, the possible vertices are ( - 3, - 1 ) and ( 3, - 1 ) or ( - 3, 11 ) and ( 3, 11 )