Question

Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions? –5 –3 3 4

Answer 1

-5

Explanation:

It's A on edge I'm doing the assignment rn

Answer 2

b = -5

Explanation:

You needy to calculate the Discriminant = b² - 4ac

If D is zero there is one real solution,

If D less then zero there are no real solutions

Only if D is bigger then zero, there are two real solutions.

x² - 5x + 5 D > 0 so 2 real solutions

see attachment.

x² - 3x + 5 D < 0 so no real solutions

x² + 3x + 5 D < 0 so no real solutions

x² + 4x + 5 D < 0 so no real solutions