Final answer:
The zeroes of the quadratic function f(x) = x² - x - 2 are x = -2 and x = 1.
Step-by-step explanation:
The zeroes of the quadratic equation, f(x) = x² - x - 2, can be found by setting the equation equal to zero and solving for x. We can rearrange the equation to:
x² - x - 2 = 0
Then, we can use the quadratic formula, which states that for an equation of the form ax² + bx + c = 0, the solutions are given by:
x = (-b±√(b² - 4ac)) / (2a)
In this case, a = 1, b = -1, and c = -2. Substituting these values into the quadratic formula, we get:
x = (-(-1)±√(((-1)² - 4(1)(-2)))) / (2(1))
Simplifying this expression gives x = (-1±√(1 + 8)) / 2. This can be further simplified to:
x = (-1±√9) / 2
Which gives us x = (-1±3) / 2. Therefore, the zeroes of the function f(x) are x = -2 and x = 1.