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Find the oxidation number of chromium in K2Cr2O7​

User Brrwdl
by
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1 Answer

7 votes

Answer:

The oxidation state of chromium is +6

Step-by-step explanation:

Let the oxidation number be x

Since The sum of all oxidation numbers are equal to zero,

So,

(+1)2 + 2x + (-2)7 = 0

+2 +2x -14 = 0

2x-12 = 0

2x = +12

Dividing 2 to both sides

x = +6

User Eitann
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