Question

What is the factored form of 27a6+8g12?

Answer 1

`\left(2g^4+3a^2\right)\left(4g^8-6g^4a^2+9a^4\right)`

Explanation:

`27a^6+8g^(12)`

`\mathrm{Rewrite\:}27a^6+8g^(12)\mathrm{\:as\:}\left(3a^2\right)^3+\left(2g^4\right)^3`

`\mathrm{Apply\:Sum\:of\:Cubes\:Formula:\:}x^3+y^3=\left(x+y\right)\left(x^2-xy+y^2\right)`

`\left(3a^2\right)^3+\left(2g^4\right)^3=\left(3a^2+2g^4\right)\left(3^2a^4-3\cdot \:2g^4a^2+2^2g^8\right)`

`=\left(2g^4+3a^2\right)\left(2^2g^8-3\cdot \:2g^4a^2+3^2a^4\right)`

`=\left(2g^4+3a^2\right)\left(4g^8-6g^4a^2+9a^4\right)`

Answer 2

b

Explanation:

correct on edge 2021

the other one isnt even an option