Question

What is the range of the function y=
= VX+5?
Oy2-5
Oy20
O yzv5
Oy25

Answer 1

A) y² -5

The range of the given function x = y² -5

Explanation:

Explanation:-

Given f(x) = √x +5

Let y = f(x) = √x +5

y = √x +5

squaring on both sides, we get

⇒ y² = x +5

⇒ x = y² -5

The range of the given function x = y² -5