Question

Show work plzzz

Unknown Metal Bar #8
Mass of Unknown Metal bar 11.3g
Length of bar 13.90cm
Width of bar 2.9cm
Thickness of bar 0.081cm

1. Calculate the volume of the bar:

2. Calculate the (experimental) density of the bar:

3. Based on the provided list of (true) densities, what is the possible identity of the Unknown metal?

4. What is the percent difference between the true density of your metal and the calculated density?
= | − | ∗ 100%

Answer 1

1= Volume

= Length x breath x height

= 13.90 x 2.9 x 0.081

=3.26511

2= Density = Mass ÷ volume

= 11.3 ÷ 3.26511

= 3.461 (3d.p)

idk the rest because you haven't shown a picture of the rest

Answer 2

1. 3.3 cm³; 2. 3.5 g/cm³; 3. barium; 4. 4%

Step-by-step explanation:

Experimental data:

Mass = 11.3 g

Length = 13.90 cm

Width = 2.9 cm

Thickness = 0.081 cm

Calculations:

1. Volume of bar

V = lwh = 13.90 cm × 2.9 cm × 0.081 cm = 3.3 cm³

2. Experimental density

`\text{Density} = (m)/(V) = \frac{\text{11.3 g}}{\text{3.27 cm}^(3)} = \textbf{3.5 cm}^{\mathbf{3}}`

3. Identity of metal

The three most likely metals are scandium (3.00 g/cm³), barium (3.59 g/cm³), and yttrium (4.47 g/cm³)

The metal is probably barium.

4. Percent difference

`\begin{array}{rcl}\text{Percent difference}&= &\frac{\lvert \text{ True - Calculated}\lvert}{ \text{True}} * 100 \,\%\\\\& = & (\lvert 3.59 - 3.5\lvert)/(3.59) * 100 \, \% \\\\& = & (\lvert 0.1\lvert)/(3.59) * 100 \, \%\\ \\& = & 0.04 * 100 \, \%\\& = & \mathbf{4 \, \%}\\\end{array}\\\text{The percent difference is $\large \boxed{\mathbf{4 \, \%} }$}`