Answer:
There are no real solutions to the quadratic equation 5a² - 6a + 10 = 0.
Explanation:
We can determine the number of real solutions to a quadratic equation according to the value of its determinant, which is written with the capital letter D.
If pa² + qa + r = 0 and p > 1.
Thus, D = q² - 4pr.
If D > 0, then the equation has 2 real solutions.
If D = 0, then the equation has 1 real solution.
If D < 0, then the equation has 0 real solutions.
We can deduce D from the equation 5a² - 6a + 10 = 0 by writing the following:
p = 5
q = -6
r = 10
D = q² - 4pr
D = (-6)² - 4(5)(10)
D = 36 - 200
D = -164
D < 0
Since the determinant is negative, the equation 5a² - 6a + 10 = 0 has zero real solutions.
I hope this helps! Sorry if my English didn't really help with having a clearer explanation.