Question

An engine performs 17,640 J of work on a scooter. The scooter and riderhave a combined mass of 180 kg. If the scooter started at rest, what is the speed of the bike after the work is performed?

Answer 1

14 m/s

Step-by-step explanation:

Answer 2

14 m/s

Step-by-step explanation:

We assume that all of the work performed is translated to kinetic energy:

KE = 1/2mv² . . . . m represents mass

v = √(2KE/m) . . . . m represents mass

= √(2(17,640J/180 kg)) = √(196 m²/s²) . . . . m represents meters

v = 14 m/s

The speed of the bike is about 14 meters per second.