Given that,
Mass of water = 1.26 kg
Latent heat of vaporization of water
![L=2.26*10^(6)\ J/kg](https://img.qammunity.org/2021/formulas/physics/high-school/9xt68q8tpof8117wz9ntiz0qm8zdmo2jli.png)
We need to calculate the latent heat
Using formula of latent heat
![Q=mL](https://img.qammunity.org/2021/formulas/physics/college/icjjiz2xfse7pxl9mvn0pajwt0ffv4dacj.png)
Where, Q = energy
m = mass
L = latent heat of vaporization
Put the value into the formula
![Q=1.26*2.26*10^(6)](https://img.qammunity.org/2021/formulas/physics/high-school/824od9k53tdsv5t7mkhho9nv0uy4rh53b5.png)
![Q=2847600\ J](https://img.qammunity.org/2021/formulas/physics/high-school/6hlrld91br81h0fhiib6isrbkd6a5x00mk.png)
![Q=2.84*10^(6)\ J](https://img.qammunity.org/2021/formulas/physics/high-school/wt7d0mkrhm91iq0cfbpy5gjo9qqwbu0i47.png)
The temperature changes liquid to steam.
So, The temperature will be increases.
Hence, The latent heat is
and temperature increases.