Answer:
a). Graph (E)
b). Graph (A)
c). Graph (B)
d). Graph (D)
Explanation:
a). y = x³ + 2x² - 1
Since highest degree of this function is odd, therefore, the graph will start form the left and rises to the right.
Therefore, graph (E) is the answer.
b). y = 2x²- x - 3
Its a quadratic function therefore, option A will be the graph.
c).
![y=(1)/(x)+1](https://img.qammunity.org/2021/formulas/mathematics/high-school/r1xsomod9wsvwrj0n4vyi4gavpocjmobv1.png)
Vertical asymptote : x = 0
Horizontal asymptote : y = 1
Therefore, option B will be the graph for this function.
d). y = 2 - 3x² - x³
y = -x³ - 3x² + 2
Highest power of the function is odd and the coefficient of highest degree term is negative.
Therefore, the graph will start from the top left and will go down to the right of the graph.
Option D will be the graph.