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Part 3. Identify the X intercepts for

y = (x+4)^2-9​

Part 3. Identify the X intercepts for y = (x+4)^2-9​-example-1
User Yangsuli
by
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2 Answers

7 votes

To find the x intercepts, plug in y = 0 and solve for x

y = (x+4)^2 - 9

0 = (x+4)^2 - 9 ... replace y with 0

9 = (x+4)^2

(x+4)^2 = 9

x+4 = plus/minus sqrt(9)

x+4 = sqrt(9) or x+4 = -sqrt(9)

x+4 = 3 or x+4 = -3

x = 3-4 or x = -3-4

x = -1 or x = -7

You have the correct answers. Nice work.

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Checking each answer:

Plug x = -1 into the original equation. You should get y = 0 as a result

y = (x+4)^2 - 9

y = (-1+4)^2 - 9

y = (3)^2 - 9

y = 9-9

y = 0 .... so this confirms x = -1 as a solution

The same should apply for the other potential solution x = -7

y = (x+4)^2 - 9

y = (-7+4)^2 - 9

y = (-3)^2 - 9

y = 9-9

y = 0 .... this confirms x = -7 as well

User Dragonfly
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4.9k points
3 votes

Answer:

x = -1 or x = -7

Explanation:

y = (x + 4)^2 - 9​

To find x-intercept, set y = 0

=> (x + 4)^2 - 9​ = 0

=> ( x + 1)( x + 7) = 0

=> x = -1 or x = -7

User Victor Ionescu
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5.0k points