Answer:
Answer is below. Hope this helps you!
Explanation:
(i)v = u + at
(ii) s = ut + 1/2 *at²
(iii)2as = v²-u²
Examples:
A train starting from rest attains a velocity of 72km/h in 5 minutes. Assuming that the acceleration is uniform, find (i) the acceleration and (ii) the distance travelled by the train for attaining this velocity.
72km/h = 20m/s
(i) use v= u+ at
20 = 0 + a*300
20 = 5a
20 / 300= a
1/15 ms² = a
to find distance
use 2as= v²-u²
2 *1/15 * s = (20) - 0²
2/15s = 400
s = 400 * 15/2
s = 3000m = 3 km
a car accelerates with a uniform acceleration of 1m/s². it starts with a velocity of 18km/h and reaches 36 km/h in 5 seconds find the distance travelled.
18 km /h = 5m/s
36km/h = 10m/s
use - s= ut + 1/2at²
s = 5 * 5 + 1/2 * 1 * (5)²
s = 25 + 25/2
s = 37.5 meters