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F(x)=x^2-2x+3; f(x)=-2x+28

F(x)=x^2-2x+3; f(x)=-2x+28-example-1
User Eric Farr
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1 Answer

0 votes

Answer:

(-5, 38) and

(5,18)

Explanation:


x^2-2x+3=-2x+28\\<=> x^2-2x+3+2x=28\\<=> x^2 = 28-3=25\\<=> x^2-25=0\\<=> x^2-5^2 =0\\<=> (x-5)(x+5)=0\\<=> x = 5 \ or \ x=-5

so the solutions are

(-5, 38) and

(5,18)

User Gary Schreiner
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