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4 votes
X^2y^8/x^7y^6 if x= -2 and y= 4

1 Answer

5 votes

Answer:

-
(1)/(2)

Explanation:

Given


(x^2y^8)/(x^7y^6)

=
(y^((8-6)) )/(x^((7-2)) )

=
(y^2)/(x^5) , substitute values

=
(4^2)/((-2)^(5) )

=
(16)/(-32)

= -
(1)/(2)

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