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4 votes
Find sin3A, cos
3A and tan 3A when sin=1/2


1 Answer

1 vote

Answer:

Sin 3A = 1

cos 3A = 0

tan 3 A = undefined

Explanation:


\sin A = (1)/(2) \\ \therefore \: \sin A = \sin \: 30 \degree.. \bigg( \because \: \sin \: 30 \degree = (1)/(2) \bigg) \\ \therefore \: A = 30 \degree \\ \\ now \\ \sin 3A =\sin (3 * 30 \degree)= \sin \: 90 \degree = 1 \\ \\ \cos 3A =\cos (3 * 30 \degree)= \cos \: 90 \degree = 0\\\\ \tan 3A =\tan (3 * 30 \degree)= \tan \: 90 \degree = \infty

User Chinoto Vokro
by
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