Answer:
Explanation:
Hello
I believe there is an error in the question
we have two equations and need to find x and y
![(1) (1)/(4)x+(1)/(2)y=(5)/(8)\\(2) (3)/(4)x-(1)/(2)y=3(3)/(8)](https://img.qammunity.org/2021/formulas/mathematics/college/xwypvrx94xa3fex6y6gbmueo3zll0enw5n.png)
let s multiply by 8 so that we can get rid of the fractions
(1) becomes 2x+4y=5
(2) becomse 6x-4y=9
if we sum it gives
2x+4y+6x-4y=9+5
8x=14
x = 14/8 = 7/4
and then from the first equation
4y = 5 - 7/4
<=> 16y = 20-7 = 13
y = 13/16
the solutions is (7/4,13/16)