Question

There are 8 students in our Math class left to give their presentations. Today

we will have time for 5 presentations. How many different ways can the
teacher choose the presenters?

OA) 56
OB) 112
OC) 168
OD) 336

Answer 1

Answer: Choice A

Explanation:

Answer 2

Option A. 56

Explanation:

The question talks about chosing 5 presenters out of 8 presenter.

This can be achieved b using the following formula:

nCr = n! /r! (n–r)!

n = 8

r = 5

8C5 = 8! / 5! (8 – 5)!

8C5 = 8! / 5! 3!

8C5 = (8 x 7 x 6) / (3 x 2 x 1)

8C5 = 56

Therefore, there are 56 ways in which the teacher can chose the presenters.