Answer:
A. Domain : (-∞, ∞)
B. Function is increasing in the interval (-2, 0) and (2, ∞)
Decreasing in the interval of (-∞, -2) and (0, 2).
Explanation:
A. Given function is, y = |2x - 1|
This function is the transformed form of the parent function, y = |x|
Domain of the parent function is x is a set of real numbers
Therefore, domain of the transformed function will be the same as the domain of the parent function.
Domain of the function = x is a real number
B. Given function is f(x) =
![(x^2-4) ^{(2)/(3) }](https://img.qammunity.org/2021/formulas/mathematics/middle-school/hhk9hsyzet1nv4ws7l23o0ut7il54warpv.png)
Domain of the function : (-∞, ∞)
Critical points of the function are,
⇒ x = 0, ±2
Now we find the three intervals where we have to check the function to be increasing or decreasing.
(-∞ -2), (-2, 0), (0, 2), (2, ∞)
Derivative of the function f(x),
f'(x) =
![\frac{4x}{3(x^2-4)^{(1)/(3) } }](https://img.qammunity.org/2021/formulas/mathematics/middle-school/o0jqc524hah3dbooxdjm8jjjx6dpvacd6m.png)
Here, f'(x) < 0 for (-∞, -2)
f'(x) > 0 for (-2, 0)
f'(x) < 0 for (0, 2)
f'(x) > 0 for (2, ∞)
Therefore, given function is increasing in the interval (-2, 0) and (2, ∞)
And it's decreasing in the interval of (-∞, -2), and (0, 2).