Answer:
Part A: D.

Part B: C.

Explanation:
For part A) we just have to plug in 0 for x and solve for y until we find the equation that says 3 is the value for y when x is 0. For purposes of speeding up the process the correct answer is D. I will show how to check for it now.
The equation:

Now plug in 0 for x.

Now solve.
y = (1)(3)
y = 3
This proves that this is the correct answer.
For part B) we just have to plug in the give values for x separately and check for each value of x that it equals 0. For the purpose of speeding up the process the correct answer is C. I will show how to check for it now.
The equation:

Now plug in x for 0 and solve:



This equation is true, now we check for the other value of x, 3.



This is also true so that means this is the correct answer.