Answer:
![1.2* 10^3 rNe](https://img.qammunity.org/2021/formulas/chemistry/college/xin7bbdfz8t8j96hic7lijyd42kaqxntt3.png)
Step-by-step explanation:
Given that
Speed of neon = 350 m/s
Un-certainity in speed= (0.01 ÷ 100) × 350
= 0.035 m/s
As per heisenberg uncertainty principle
....... (i)
substituting the values in equation (i)
![\triangle X = 4.49 * 10^-^8 m](https://img.qammunity.org/2021/formulas/chemistry/college/1812dtufrl3nkdzcnyfjm7gdta90dax1n9.png)
In terms of rNe i.e 38 pm =
![38* 10^-^1^2](https://img.qammunity.org/2021/formulas/chemistry/college/p0g2oqn46vklhjdijlfvd1f9rt0uref80j.png)
![\triangle X = (4.49* 10^-^8)/(38* 10^-^1^2)](https://img.qammunity.org/2021/formulas/chemistry/college/v3af56gp0i2vjafrvql58chf6h90f45w6c.png)
![= 0.118 * 10^4 * (rNe)](https://img.qammunity.org/2021/formulas/chemistry/college/8boygd4y02x1gq3eil4flquyi4o22cj6ax.png)
![= 1.18* 10^3 rN](https://img.qammunity.org/2021/formulas/chemistry/college/bbhjo5avbme0yao2lt6wccbm98br5lahhm.png)
Therefore the smallest possible length of the box inside in which the atom could be known for locating with certainty is
![1.2* 10^3 rNe](https://img.qammunity.org/2021/formulas/chemistry/college/xin7bbdfz8t8j96hic7lijyd42kaqxntt3.png)