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A certain ore contains 21 percent gold. How much ore (in tons) is needed to obtain 882 tons of gold?
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21 votes
A certain ore contains 21 percent gold. How much ore (in tons) is needed to obtain 882 tons of gold?

User BertC
by
5.6k points

1 Answer

10 votes

Answer:

it would be 4200 ore

Explanation:

because 882/.21

User Greg Price
by
5.0k points
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