Answer:
1) 0 Ω
2) jΩ
3) 0 Ω
4) -10j Ω
5) 10Ω
6) -9j Ω
Step-by-step explanation:
Given that R=10Ω,L=5mH,C=500μF and The source voltage is 10cos(200t+45°)
The source voltage is given by

Therefore comparing with the source voltage, the angular frequency w = 200 rad/s
a) The impedance of the inductor is given by:

The real part is 0 Ω and
the imaginary part is j Ω
b) The impedance of the capacitor is given by:

The real part is 0 Ω and
the imaginary part is -10j Ω
c) The total impedance of the circuit is given by:

The real part is 10Ω
The Imaginary part is -9j Ω