Question

A remote controlled plane accelerates to a velocity of 21.0 m/s while covering a distance of 87.4 m in 6.11 s. What was the plane's initial velocity?

Answer 1

71.6

Δx = 87.4 m

v = 21.0 m/s

t = 6.11 s

Find: v₀

Δx = ½ (v + v₀) t

87.4 m = ½ (21.0 m/s + v₀) (6.11 s)

v₀ = 7.61 m/s

Answer 2

7.61 m/s

Step-by-step explanation:

Given:

Δx = 87.4 m

v = 21.0 m/s

t = 6.11 s

Find: v₀

Δx = ½ (v + v₀) t

87.4 m = ½ (21.0 m/s + v₀) (6.11 s)

v₀ = 7.61 m/s