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a vector points 12.0 units along the x-axis and 9.00 units along the y-axis. find the magnitude of the vector

User Rocketas
by
5.5k points

2 Answers

7 votes

Final answer:

The magnitude of the vector is 15.0 units.

Step-by-step explanation:

To find the magnitude of the vector, we can use the Pythagorean theorem. The vector points 12.0 units along the x-axis and 9.00 units along the y-axis. These are the x- and y-components of the vector. Let's call the x-component A and the y-component B. According to the Pythagorean theorem, the magnitude of the vector R is given by:

R = sqrt(A^2 + B^2)

Substituting the values, we get:

R = sqrt((12.0)^2 + (9.00)^2) = sqrt(144 + 81) = sqrt(225) = 15.0

Therefore, the magnitude of the vector is 15.0 units.

User Chazbot
by
5.9k points
2 votes

Step-by-step explanation:

R =
\sqrt{(12.0)^(2) + (9.00)^(2)} = 15 UNIDADES

User Germanio
by
5.9k points