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Solve: 4x^-2 – 3x^-1– 1 = 0

1 Answer

3 votes

Answer:

1, -4

Explanation:

  • 4x^-2 – 3x^-1– 1 = 0

Let x^-1 = 1/x = y

  • 4y^2 - 3y - 1 = 0
  • 4y^2 - 4y + y - 1 = 0
  • (y - 1) (4y + 1) = 0

1. Root 1

  • y - 1 = 0
  • y = 1
  • 1/x= 1
  • x = 1

2. Root 2

  • 4y + 1 = 0
  • 4y = -1
  • y = -1/4
  • 1/x = - 1/4
  • x = -4
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