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Why is the product of a rational number and an irrational number Irrational?

Why is the product of a rational number and an irrational number Irrational?-example-1
User Homm
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6.8k points

2 Answers

6 votes

Answer:

Because the product is always non-termination,non-repeating decimal.

Explanation:

If we have
a is irrational;
b is rational such that
b \\eq 0 , then
a \cdot b is irrational.

A way to represent this is:


a\in\mathbb{R}\setminus\mathbb{Q}, b\in\mathbb{Q},ab\in\mathbb{Q}\implies a\in\mathbb{Q}\implies\text{Contradiction}\therefore ab\\ot\in\mathbb{Q}.

Note that we have a contradiction, because
a is not a rational number, as I stated in the beginning. Therefore, ab is irrational.

User Dicle
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7.0k points
1 vote

Answer: A

Explanation:

Multiplying an irrational number by a rational number will always be an irrational number because irrational numbers do not repeat and terminate.

So for example multiplying pi by a rational like two you will have an irrational number because pi is an irrational number.


\pi * 2 = 6.28318530718 as you could see that is an irrational number because there is no repetition or termination.

User Danny Fang
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8.1k points