Answer:
a) -2 [ 3a-4(a-2-a) ]
= -2[ 3a - 4×(-2) ]
= -2( 3a + 8 )
= -6a-16
b) 5 [ 3c- ( d-2c-2d ) ]
= 5 [ 3c - (-d -2c ) ]
= 5 ( 3c + d + 2c )
= 5 ( 5c + d )
= 25c + 5d
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