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How many milliliters of a 2.5 M LiOH solution are needed to completely neutralize 25 mL of a 1.0 M H2SO4 solution?

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Answer:

20 ml.

Step-by-step explanation:

molarity of LioH (M1)=2.5M

Volume of LioH( V1)=?

Normality of LiOH (N1)=M1×valence factor=2.5×1=2.5 N

Volume of acid H2SO4(V2)=25 ml

molarity of acid H2SO4(M2)=1.0 M

Normality of acid H2SO4(N2)=M2×valance factor=1.0×2=2.0

now,according to normality equation,

V1.N1=V2.N2

or,V1×2.5=25×2

or,V1=50/2.5

or,V1=20 ml

Therefore, V1=20 ml.

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