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[64] {y}^{2} [+4y-3]

1 Answer

4 votes

Answer:

(16y-3) (4y+1)

Explanation:

using quadratic formula i.e.ay^2+by+c=0

64y^2+4y-3

64y^2+16y-12y-3

16y(4y+1)-3(4y+1)

(16y-3) (4y+1)

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User ChaoYang
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