Question

If cos0 =1/3
then sin0=?

Answer 1

sin θ = +/- (2√2)/3

Explanation:

cos θ = 1/3

cos²θ + sin²θ = 1

(1/3)² + sin²θ = 1

sin²θ = 1 - 1/9

√(sin²θ) = +/-√(8/9)

sin θ = +/- (2√2)/3