Question

What is the equation of the line that is parallel to the line y - 1 = 4(x + 3) and passes through the point (4, 32)?

VX
O y=*x+33
O y=-*x+36
O y = 4x - 16
O y = 4x + 16
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Answer 1

y = 4x + 16 (fourth answer choice)

Explanation:

From the given equation we can immediately discern that the slope of these lines is 4 (as they are parallel).

Starting with the slope-intercept formula y = mx + b, we get:

32 = 4(4) + b, or 16 = b, or y = 4x + 16