Question

if water absorbs 0.779j and has a mass of 0.4866g, how much would its temperature go up? a) 0.383 C b) 7.458 C c) 0.137 C d) 0.233 C

Answer 1

A is the answer (0.383)

Step-by-step explanation:

Formula: q=mcΔt

q=heat m=mass c=specific heat capacity Δt=change in temperature

q=0.779j m=0.4866g c=4.184j/C t=??

(waters specific heat is usually given or memorized)

0.779=(0.4866)(4.184)(?)

0.779/(0.4866)(4.184)=0.3826

Δt=0.383