a 10. kg ball thrown into the air. it is going 3.0 m/s when thrown. how much potential energy will it have at the top?

Sinned asked Mar 23, 2023

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Sinned asked Mar 23, 2023

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16 votes

Answer:

45 j

Step-by-step explanation:

At the top, the KE will have been converted to PE

KE = 1/2 mv^2 =PEat-top = 1/2 10 *3^9 = 45 j

Elliott B answered Mar 29, 2023

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