Question

The complete factorization of -12x^3 + 14x^2 +6x is -2x(ax + 1)(2x-3). What is the value of a?

Answer 1

a = 3

Explanation:

-12x³+14x²+6x = -2x(ax+1)(2x-3)

Divide both sides by -2x(2x-3)

`(-2x(ax+1)(2x-3))/(-2x(2x-3)) = - (12x^(3) )/(-2x(2x-3)) + (14x^(2) )/(-2x(2x-3)) +(6x)/(-2x(2x-3))`

ax+1=3x+1

Subtract 1 from both sides

ax=3x

Divide both sides by x

a=3