Find the equation of a line passing through the point (6,−5) and parallel to the line y = 7x + 1. answers : y = 7x − 47 y = −17x + 41 y = −17x +477 y = 7x − 29

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asked Oct 11, 2021 205k views

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Find the equation of a line passing through the point (6,−5) and parallel to the line y = 7x + 1. answers : y = 7x − 47 y = −17x + 41 y = −17x +477 y = 7x − 29

Mathematics
middle-school

Roman Nazarkin asked

by Roman Nazarkin

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Answer:

y = 7x-47

Explanation:

$y = 7x + 1.\\(6,-5)\\m= 7\\x1= 6\\y1 = -5\\y-y1=m(x-x1)\\y-(-5) = 7(x-6)\\y+5=7x-42\\y=7x-42-5\\y = 7x-47$

Hershi answered Oct 15, 2021

by Hershi

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y = 7x-47

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