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Find the equation of a line passing through the point (6,−5) and parallel to the line y = 7x + 1. answers : y = 7x − 47 y = −17x + 41 y = −17x +477 y = 7x − 29

Find the equation of a line passing through the point (6,−5) and parallel to the line y = 7x + 1. answers : y = 7x − 47 y = −17x + 41 y = −17x +477 y = 7x − 29
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Find the equation of a line passing through the point (6,−5) and parallel to the line y = 7x + 1. answers : y = 7x − 47 y = −17x + 41 y = −17x +477 y = 7x − 29

User Roman Nazarkin
by
8.1k points

1 Answer

2 votes

Answer:

y = 7x-47

Explanation:


y = 7x + 1.\\(6,-5)\\m= 7\\x1= 6\\y1 = -5\\y-y1=m(x-x1)\\y-(-5) = 7(x-6)\\y+5=7x-42\\y=7x-42-5\\y = 7x-47

User Hershi
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