Question

Can anyone please explain me this,would be appreciated

Brian, a scientist, is writing a research paper on projectile motion. during one of his experiments, he throws a ball from a point marked as point a, with a certain velocity in the horizontal direction. the ball travels a horizontal distance of 0.6 meter in the 1st second, 1.2 meters in the 2nd second, 1.8 meters in the 3rd second, and so on. it hits the ground on the 8th second. brian marks the point where the ball landed as point b. calculate the distance between point a and point b.

Answer 1

The distance between point A and point B is 21.6 meters.

Step-by-step explanation:

To calculate the distance between point A and point B, we can use the formula for the horizontal distance traveled by an object in projectile motion.

Since the ball travels a horizontal distance of 0.6 meters in the 1st second, 1.2 meters in the 2nd second, and so on, we can see that the horizontal distance traveled increases by 0.6 meters every second.

Since the ball hits the ground on the 8th second, we can calculate the total horizontal distance traveled by adding up the distances traveled in each second:
0.6 + 1.2 + 1.8 + ... + 4.8

This is an arithmetic series with a common difference of 0.6, so we can use the formula for the sum of an arithmetic series:

Sum = (n/2)(2a + (n-1)d),

where n is the number of terms, a is the first term, and d is the common difference.

In this case, the number of terms (n) is 8, the first term (a) is 0.6, and the common difference (d) is also 0.6. Plugging these values into the formula, we get:

Sum = (8/2)(2(0.6) + (8-1)(0.6)) = 4(1.2 + 0.6(7)) = 4(1.2 + 4.2) = 4(5.4) = 21.6

Therefore, the distance between point A and point B is 21.6 meters.