Answer:
The appended bits are 1100, the sender sending the data after adding is 100100110111100.
Note: Kindly find an attached document to part of the solution for the necessary steps to the complete calculation at both ends is attached below.
Step-by-step explanation:
Solution
Given that:
We have the data bits of 10010011011 and the divisor is 10011
Thus,
We have to append four 0's at the end of data bits
The appended bits are 1100
At the receiver side the bits are 0000
Therefore sender sending the data after adding is 100100110111100